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2P_0 = P_0 e^0.08t - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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a_2 &= 2(2)^2 + 3(2) + 1 = 8 + 6 + 1 = 15,\\
a_3 &= 2(3)^2 + 3(3) + 1 = 18 + 9 + 1 = 28,\\
a_4 &= 2(4)^2 + 3(4) + 1 = 32 + 12 + 1 = 45,\\
a_5 &= 2(5)^2 + 3(5) + 1 = 50 + 15 + 1 = 66.
Now, sum these terms:
+ 15 + 28 + 45 + 66 = 160.
Thus, the sum of the first five terms is \(\boxed{160}\).
Question:** A middle school student is exploring functions and their c...
First, evaluate \(f(4)\):
f(4) = 3(4) - 2 = 12 - 2 = 10.

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