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Home » A regular hexagon divides into 6 equilateral triangles, each with side = radius = 6 cm. - 500apps

A regular hexagon divides into 6 equilateral triangles, each with side = radius = 6 cm. - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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From (2): $ a = 70 - 4d $
Substitute into (1): $ 2(70 - 4d) + 3d = 60 $ → $ 140 - 8d + 3d = 60 $...
Then $ a = 70 - 4(16) = 70 - 64 = 6 $
So annual retreat sequence:
Year 1: 6
Year 2: 22
Year 3: 38
Year 4: 54
Year 5: 70
Year 6: 86

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S(5) = 2(5)^2 + 3(5) + 1 = 2(25) + 15 + 1 = 50 + 15 + 1 = 66
Next, calculate the score for the 3rd game:
S(3) = 2(3)^2 + 3(3) + 1 = 2(9) + 9 + 1 = 18 + 9 + 1 = 28
The score difference between the 5th and 3rd games is:
S(5) - S(3) = 66 - 28 = 38
Thus, the score difference is:
\boxed{38}
A rectangular plot of land has a perimeter of 100 meters. Find the max...
Let the length and width of the rectangle be \( l \) and \( w \), resp...
2l + 2w = 100 \quad \Rightarrow \quad l + w = 50

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