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Home » \(a(1)^2 + b(1) + c = 2 \rightarrow a + b + c = 2\) - 500apps

\(a(1)^2 + b(1) + c = 2 \rightarrow a + b + c = 2\) - 500apps

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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\binom{4}{2} = 6, \quad \left(\frac{1}{6}\right)^2 = \frac{1}{36}, \qu...
So:
P(2) = 6 \times \frac{1}{36} \times \frac{25}{36} = \frac{150}{1296} =...
Thus, the probability is $\boxed{\dfrac{25}{216}}$
Question: How many distinct words can be formed using all the letters...
Solution: First, identify the vowels and consonants in "BIOINFORMATICS...
Vowels: I, O, I, A, I → 5 vowels (I appears 3 times, O and A once)
Consonants: B, N, F, R, M, T, C, S → 8 consonants (all distinct)
Treat the block of vowels as a single "super-letter". So we are arrang...
1 vowel block

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