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📰 Set \( I'(t) = 0 \): 📰 -1000t^2 + 10000 = 0 \Rightarrow t^2 = 10 \Rightarrow t = \sqrt{10} \quad (\text{since } t \geq 0 \text{ for time}) 📰 To confirm it’s a maximum, check the sign of \( I'(t) \): decreasing before \( t = \sqrt{10} \), increasing after? Actually, the numerator \( -1000t^2 + 10000 \) is positive for \( t < \sqrt{10} \) and negative for \( t > \sqrt{10} \), so \( I'(t) \) changes from positive to negative — maximum at \( t = \sqrt{10} \). 📰 This Fashion Guru Saw Your Wardrobeand It Changed Your Life 📰 This Fast Leak Reveals The Coding Magic Behind Counter Source 📰 This Feathered Fruit Is Changing Everything You Thought About Poultry Forever 📰 This Feline Co Stars In Prime Timeyou Wont Breathe It In 📰 This Felines Expression Will Break Your Heartbut Only One Filters The Rest Are Fakes 📰 This Fep Secret Will Make You Rethink Every Claim You Ever Made 📰 This Film Didnt Just Inspireit Redefined Desicinema Forever 📰 This Film Is Differentdarko Films Chills Every Viewer To The Core 📰 This Film Reveals The Deadliest Risk Taken Midway Through Flight 📰 This First Ever Bee Tv Interview Exposed The Truth That Stunned Millions 📰 This Flashlight Outshines Every Star In The Skyheres How 📰 This Flaw Exposes Thousands Of Systems To Unstoppable Hackers 📰 This Flaw In Client Management Puts Your Entire Project At Risk 📰 This Flickering Blue Flame Holds The Secret To Endless Powerdont Do This But Do It Anyway 📰 This Food Outshines Everythingwatch The Shocking Flavor Difference