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\(\boxed{-11 - 5\sqrt5}\) - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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where \( z = \sqrt{a^2 + b^2} \). Also, the area can express in terms...
A = c \cdot s,
where \( s = \frac{a + b + z}{2} \) is the semi-perimeter.
A_{\text{circle}} = \pi c^2.
Thus, the ratio \( R \) of the area of the circle to the area of the t...
R = \frac{\pi c^2}{A} = \frac{\pi c^2}{c \cdot s} = \frac{\pi c}{s}.
For a right triangle, it is known that \( r = \frac{a + b - c}{2} \),...
R = \frac{\pi c}{s}.
But recall a standard identity: in any triangle, \( \frac{A}{s} = r \)...
For a right triangle, the inradius is \( c = \frac{a + b - z}{2} \), a...

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