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Home » Distance: \( 15 \times 2.5 = 37.5 \, \textkm \) - 500apps

Distance: \( 15 \times 2.5 = 37.5 \, \textkm \) - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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📌 5Question: A historian analyzing ancient architectural blueprints discovers a right triangle with hypotenuse $ z $ and inradius $ c $. If the triangleâs area is $ A $, what is the value of $ rac{\pi c^2}{A} $, the ratio of the incircleâs area to the triangleâs area?

📌 Solution: For a right triangle with legs $ a $ and $ b $, and hypotenuse $ z $, the inradius is given by $ c = rac{a + b - z}{2} $. The area $ A $ of the triangle is $ rac{1}{2}ab $. The area of the incircle is $ \pi c^2 $. Using the identity $ a^2 + b^2 = z^2 $, and expressing $ a + b $ in terms of $ z $ and $ c $, we find $ a + b = z + 2c $. Also, the semiperimeter $ s = rac{a + b + z}{2} = rac{2z + 2c}{2} = z + c $. The area can also be written as $ A = r \cdot s = c(z + c) $. Therefore, the ratio becomes:

📌 rac{\pi c^2}{A} = rac{\pi c^2}{c(z + c)} = rac{\pi c}{z + c}

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