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Home » \frac1f = \frac130 + \frac160 = \frac260 + \frac160 = \frac360 = \frac120 - 500apps

\frac1f = \frac130 + \frac160 = \frac260 + \frac160 = \frac360 = \frac120 - 500apps

📅 March 15, 2026 👤 scraface

Mar 15, 2026

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\( a_4 = 3(4)^2 + 2(4) + 1 = 57 \)
\( a_5 = 3(5)^2 + 2(5) + 1 = 86 \)
Sum: \( 6 + 17 + 34 + 57 + 86 = 200 \).
A quadratic equation \( x^2 - 5x + 6 = 0 \) is given. Find the roots a...
Factor: \( (x - 2)(x - 3) = 0 \).
Roots: \( x = 2 \) and \( x = 3 \).
Product of roots: \( 2 \times 3 = 6 \).
A circle is inscribed in a square with a side length of 10 cm. Find th...
Area of the square: \( 10^2 = 100 \) square centimeters.
Radius of the circle: \( \frac{10}{2} = 5 \) cm.

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