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Home » h' = \sqrt{100 - \frac(b+4)^24} - 500apps

h' = \sqrt{100 - \frac(b+4)^24} - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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= 2 \cdot \frac{S^2}{5}
= \frac{2S^2}{5}
Multiply both sides by 5 to eliminate the fraction:
= 2S^2
= S^2
Take the square root of both sides to solve for \( S \):
S = \sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5}
Thus, the community size \( S \) is \(\boxed{5\sqrt{5}}\).
Question:** A bioinformatics researcher is modeling the growth rates o...
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