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Home » "How These Iconic Actors Got Cast in *Monk* – The Inside Story That Shocks Fans! - 500apps

"How These Iconic Actors Got Cast in Monk – The Inside Story That Shocks Fans! - 500apps

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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📌 5Question: Define $ Q(n) = n^2 - rac{n^4}{4} $ for all integers $ n \geq 1 $. If $ b_n $ is a sequence such that $ b_1 = 2 $ and $ b_{n+1} = Q(b_n) $, find $ b_3 $.

📌 Solution: Start with $ b_1 = 2 $. Compute $ b_2 = Q(2) = 2^2 - rac{2^4}{4} = 4 - rac{16}{4} = 4 - 4 = 0 $. Then compute $ b_3 = Q(0) = 0^2 - rac{0^4}{4} = 0 - 0 = 0 $. Thus, $ b_3 = oxed{0} $.

📌 Question: A high-performance computing algorithm processes data in nested loops, where the number of operations after $ k $ iterations is modeled by $ R(k) = 3^k - rac{3^{2k}}{2} $. Find the smallest positive integer $ k $ for which $ R(k) < -1 $.

📌 Solution: Solve $ 3^k - rac{3^{2k}}{2} < -1 $. Let $ x = 3^k $ (note $ x > 0 $). The inequality becomes $ x - rac{x^2}{2} < -1 $, or $ -rac{x^2}{2} + x + 1 < 0 $. Multiply by $-2$ (reversing inequality): $ x^2 - 2x - 2 > 0 $. Solve $ x^2 - 2x - 2 = 0 $: roots are $ x = 1 \pm \sqrt{3} $. Since $ x > 0 $, critical point is $ x = 1 + \sqrt{3} pprox 2.732 $. The quadratic is positive when $ x > 1 + \sqrt{3} $. Since $ x = 3^k $, find smallest $ k $ such that $ 3^k > 1 + \sqrt{3} $. Test $ k = 1 $: $ 3^1 = 3 > 2.732 $. Check $ R(1) = 3 - rac{9}{2} = -1.5 < -1 $. Thus, $ k = oxed{1} $.

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