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Home » If \(u = kt\) and \(v = t^2 + 1\), then - 500apps

If \(u = kt\) and \(v = t^2 + 1\), then - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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$ (8-1)\binom{8}{1} = 7 \cdot 8 = 56 $
$ (8-2)\binom{8}{2} = 6 \cdot 28 = 168 $
$ (8-3)\binom{8}{3} = 5 \cdot 56 = 280 $
Total = $8 + 56 + 168 + 280 = 512$
Second sum ($k = 4$ to $8$):
$4\binom{8}{4} = 4 \cdot 70 = 280$
$5\binom{8}{5} = 5 \cdot 56 = 280$
$6\binom{8}{6} = 6 \cdot 28 = 168$
$7\binom{8}{7} = 7 \cdot 8 = 56$
$8\binom{8}{8} = 8 \cdot 1 = 8$

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