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Home » Was ist der Wert von x in der Gleichung 3x + 5 = 20? - 500apps

Was ist der Wert von x in der Gleichung 3x + 5 = 20? - 500apps

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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The horizontal range \( R \) is given by:
\[ R = \frac{v^2 \sin(2\theta)}{g} \]
\[ R = \frac{50^2 \sin(60^\circ)}{9.8} \]
\[ R = \frac{2500 \times \frac{\sqrt{3}}{2}}{9.8} \]
\[ R \approx \frac{2500 \times 0.866}{9.8} \]
\[ R \approx \frac{2165}{9.8} \approx 220.92 \, \text{m} \]
#### 220.92
A capacitor with a capacitance of 10 µF is charged to a voltage of 100...
The energy stored in a capacitor is given by:
\[ E = \frac{1}{2} C V^2 \]

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Expand and solve:
x^2 + 2x - 3 = 8
x^2 + 2x - 11 = 0
x = \frac{-2 \pm \sqrt{4 + 44}}{2} = \frac{-2 \pm \sqrt{48}}{2}
x = \frac{-2 \pm 4\sqrt{3}}{2} = -1 \pm 2\sqrt{3}
Valid solution (since \(x > 1\)):
x = -1 + 2\sqrt{3}
A company's profit function is modeled by \(P(x) = -5x^2 + 150x - 1000...
Use the vertex formula \(x = -\frac{b}{2a}\):
x = -\frac{150}{2(-5)} = \frac{150}{10} = 15

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