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Home » We know $ an 60^\circ = \sqrt3 $, so: - 500apps

We know $ an 60^\circ = \sqrt3 $, so: - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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A_{\text{non-operational}} = 36\pi - 9\pi = 27\pi \text{ cm}^2
Thus, the area is $\boxed{27\pi}$ square centimeters.
Question: An entomologist models the flight path of a pollinating inse...
Solution: First, compute the area of the triangle using Heron’s formul...
Area $A$ is:
= \sqrt{7056} = 84 \text{ m}^2
The altitude corresponding to a side is $ h = \frac{2A}{\text{side}} $...
h_{\text{longest}} = \frac{2 \cdot 84}{13} = \frac{168}{13} \approx 12...
But we compute exactly:
h_{\text{longest}} = \frac{168}{13}

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