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yankee jk kuzuhana-chan fandom - 500apps

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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\gcd(3^{15} - 1, 3^9 - 1) = 3^3 - 1 = 27 - 1 = 26.
Therefore, the greatest common divisor is $oxed{26}$.**Question:** An...
Solution:** Start with the given equation:
rac{x+y}{x-y} + rac{x-y}{x+y} = 3.
Let \( u = rac{x+y}{x-y} \), so the second term becomes \( rac{1}{u}...
u + rac{1}{u} = 3.
Multiply both sides by \(u\) (assuming \(u
u^2 + 1 = 3u \quad \Rightarrow \quad u^2 - 3u + 1 = 0.
u = rac{3 \pm \sqrt{9 - 4}}{2} = rac{3 \pm \sqrt{5}}{2}.
So \( u = rac{3 + \sqrt{5}}{2} \) or \( u = rac{3 - \sqrt{5}}{2} \).

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